Me with this math problem asap

identify the horizontal asymptote of f(x) = quantity 6 x minus 7 over quantity 11 x plus 8.

y = 6/11  

Step-by-step explanation:

If the degrees of the numerator and denominator are equal, the horizontal asymptote is

The degrees of the numerator and of the denominator in your function are 1 and 1.

The leading coefficients are 6 and 11, so the equation of the horizontal asymptote is

The diagram below shows the graph of your function with a horizontal asymptote at y = 6/11 ≈ 0.545.

answer:   b

step-by-step explanation:

x2 = 16

x can not be a negative number because 16 is positive

the only answer would be positive 8  

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step-by-step explanation: