a chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. the premium antifreeze solution contains 80% pure antifreeze. the company wants to obtain 240 gallons of a mixture that contains 35% pure antifreeze. how many gallons of water and how many gallons of the premium antifreeze solution must be mixed?

Company will need 105 gallons of premium antifreeze solution. And 135 gallons of water to be mixed to get a solution which contains 84 gallons of pure antifreeze in 240 gallon mixture that 240 gallons of a mixture that contains 35% pure antifreeze.

Given that chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture.

The premium antifreeze solution contains 80% pure antifreeze.

The company wants to obtain 240 gallons of a mixture that contains 35% pure antifreeze.

Need to calculate gallons of water and gallons of the premium antifreeze solution must be mixed to get 240 gallons of 35% pure antifreeze.

Lets first calculate quantity of pure antifreeze required for 240 gallons having 35% of pure antifreeze.

35% of 240 gallons = 0.35 x 240 = 84 gallons of pure antifreeze.

Now need to determine quantity of premium antifreeze solution which will containing 84 gallons of pure antifreeze.

As premium antifreeze solution contains 80% pure antifreeze

=> 1 gallon of premium antifreeze solution contains 80% of 1 gallon of pure antifreeze

=> 1 gallon of premium antifreeze solution contains 0.8 gallons of pure antifreeze

=> number of gallons of premium antifreeze solution which contains 0.8 gallons of pure antifreeze = 1

So number of gallons of premium antifreeze solution which contains 1 gallons of pure antifreeze

=> Number of gallons of premium antifreeze solution which contains 84 gallons of pure antifreeze  

= 84 x number of gallons of premium antifreeze solution which contains 1 gallons of pure antifreeze  

= 84 x 1.25  = 105 gallons of premium antifreeze solution.

So company will need 105 gallons of premium antifreeze solution.

And (240 – 105 ) = 135 gallons of water to be mixed to get a solution which contains 84 gallons of pure antifreeze in 240 gallon mixture that 240 gallons of a mixture that contains 35% pure antifreeze.

40 x 50 = 2000

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