Find the equation of a parabola that opens up and has the following x intercepts (-3,0) and (4,0)

The equation of a parabola that opens up and has the following x intercepts (-3,0) and (4,0) is

We have to find the equation of a parabola that opens up and has the following x intercepts (-3, 0) and (4, 0)

x-intercepts of the parabola are (−3, 0) and (4, 0)

So, we can form an equation:

Also x = 4

x – 4 = 0

x – 4 = 0 is another factor of quadratic equation.

The quadratic function is:

Hence, the equation of the parabola is  

1: -2 3/4, -2 1/2, -14, 0, 3, 8 1/3

2: -4, -3, -2 1/2, -2 1/4, 3 1/4,

step-by-step explanation:

it will be a cylinder. with a diameter of 8 and 4 single pieces high

step-by-step explanation: