In the year 2005, a company made $6.6 million in profit. for each consecutive year after that, their profit increased by 9%. how much would the company's profit be in the year 2009, to the nearest tenth of a million dollars?

  9.3 million

Step-by-step explanation:

The growth rate of 9% per year corresponds to a growth factor of 1.09, which goes into the exponential equation ...

  profit(t) = 6.6×1.09^t . . . . . for t in years after 2005

2009 is 4 years after 2005, so the profit that year is modeled as ...

  profit(4) = 6.6×1.09^4 ≈ 9.3 . . . . million dollars

a

step-by-step explanation:

a

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)