Aresearch firm conducted a survey to determine the mean amount americans spend on coffee during a week. they found the distribution of weekly spending followed the normal distribution with a population standard deviation of $5. a sample of 64 americans revealed that x¯¯¯=$20 . what is the 95% confidence interval estimate of μ?

95% confidence Interval would be between $18.775 and $20.225.

Step-by-step explanation:

Confidence Interval can be calculated using M±ME where

And margin of error (ME) around the mean calculated as

ME= where

Using the numbers, we get:

ME= =1.225

Then 95% confidence Interval would be 20±1.225 or between $18.775 and $20.225

1/3

step-by-step explanation:

to find this, you can divide 12 by 4 which is 3 or you can multiply 4 until you reach 12 (4x3=12). both should give you 3, meaning theres three times less bananas than there are oranges.