In a different plan for area codes, the first digit could be any number from 0 through 6 , the second digit was either 7 or 8, and the third digit could be any number except 0 or 6. or 6. with this plan, how many different area codes are possible?

112 different area codes can be made.

Given, In a different plan for area codes, the first digit could be any number from 0 through 6 ,  

So, total 7 digits are possible for 1st place (i.e. 0 1 2 3 4 5 6)

The second digit was either 7 or 8,  

So, total 2 digits are possible for 2nd place (i.e. 7 8)

And the third digit could be any number except 0 or 6.  

So, total possible digits are 8 for 3rd place (i.e. 1 2 3 4 5 7 8 9)

With this plan, we have to find how many different area codes are possible?

Hence, 112 different area codes can be made.

the mean and mad

step-by-step explanation:

f(x)=2/3x+4/3 is the answer because is whose power in the senate is equal to the power of the speaker of the house?

step-by-step explanation: