Agolf ball is hit with an initial velocity of 50 m/s at an angle of 45° above the horizontal. what's the maximum height it will reach?
a. 35.4 m
b. 63.5 m
c. 82.1 m
d. 127.0 m

This problem is a projectile problem. The initial velocity is 50m/s at an optimum angle of 45. The maximum height or the height of the y component is at it's highest is asked. 

Informtion needed:
Acceleration due to gravity = 9.81m/s^2

Formula:

Hmax = ((V^2)(sin(angle))^2)/2g
Hmax = ((50^2)(sin45)^2)/(2*9.81) = 63.71 or letter B 63.5 m is the closest answer. 

Idon’t know what the answer is i wish i could