The box of a well-known breakfast cereal states that one ounce of the cereal contains 113 calories (1 food calorie = 4186 j). if 2.51% of this energy could be converted by a weight lifter's body into work done in lifting a barbell, what is the weight of the heaviest barbell that could be lifted a distance of 2.12 m?

F  =   49,56 Kgs

Step-by-step explanation:

We Know that 113 calories = 4186 J

Joules ( energy unit in MKS system   meter, kilograms , second)

and 2,51 % of 4186 is    0,0251 * 4186  = 105.07 J

That the energy available

Work is       W  =  F * d

where F is the force you have to apply and d is traveled distance

in this case F is the weight of the barbell

Then

F = W / d    ⇒    F = 105.7 / 2.12      ⇒  F  =   49,56 Kgs

i dony know

step-by-step explanation:

54 kilometers per hour

step-by-step explanation:

according to rules:

1 km = 1000 meter

which means that 1 meter = 1/1000 km

1 hour = 3600 second [ as 1 hour = 60 min = 60 *60 seconds ]

which means that 1 second = 1/3600 hour

therefore, 1 kilometer/hour =

thus to convert 15 meter per second to kilometer per hour, we multiply 15 to 3.6 kilometer/hour.

15 meter/second=   which is the required answer.