Find two consecutive odd integers such that 87 more than the lesser is six times the greater.

The two integers are 15  and  17  .

Step-by-step explanation:

Given as :

The two odd integers as , 87 more than the lesser is six times the greater

Let The first integer = x

And The second integer = x + 2

Now, According to question

First integer + 87 = 6 times ( x + 2 )

I.e x + 87 = 6 × ( x + 2 )

Or, x + 87 = 6 x + 12

or, 87 - 12 = 6 x - x

or, 75 = 5 x

Or, 5 x = 75

∴   x =

I.e  x = 15

So, The first integer = x = 15

And The second integer = x + 2 = 15 + 2 = 17

Hence The two integers are 15  and  17  .  Answer

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

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