Let xn be a sample from an n(0, 1) distribution and let yn be an independent sample from an n(1, 1) distribution.
a. determine the expected rank sum of the x’s.
b. determine the variance of the rank sum of the x’s

1/5 i hope this

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One shot. if 60% of 10 is 6, then what is 70%? we know it would be seven (since 60% is mathematically 60/100, or 6/10, then 70% is 70/100, or 7/10) but we can check anyway using ratios: 6 : 60% = x : 70%*inverse multiplicationx * 60% = 6 * 70%*divide both sides by 60%x = (6 * 70%) / 60%x = 7and since he has made 6 shots already, he would need just one more to get 7 shots or 70%. if the explanation is too confusing, comment and i will try to