The adrenaline concentrations of all sparrows in a county are normally distributed with a mean of 0.3 gram and a standard deviation of 0.02 gram. what percentage of the sparrows, taken 10 at a time, have mean concentration between 0.28 and 0.33 gram? round your answer to the nearest integer. do not include the percentage symbol in your answer.

77.45% of the sparrows, taken 10 at a time, have mean concentration between 0.28 and 0.33 gram.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The adrenaline concentrations of all sparrows in a county are normally distributed with a mean of 0.3 gram and a standard deviation of 0.02 gram. This means that .

What percentage of the sparrows, taken 10 at a time, have mean concentration between 0.28 and 0.33 gram?

This percentage is the pvalue of Z when subtracted by the pvalue of Z when . So

X = 33

has a pvalue of 0.9332

X = 28

has a pvalue of  0.1587

This means that 0.9332 - 0.1587 = 0.7745 = 77.45% of the sparrows, taken 10 at a time, have mean concentration between 0.28 and 0.33 gram.

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.