The proportion of individuals in a certain city earning more than $38 comma 00038,000 per year is 0.250.25. the proportion of individuals earning more than $38 comma 00038,000 and having a college degree is 0.120.12. suppose that a person is randomly chosen and he turns out to be earning more than $38 comma 00038,000. what is the probability that he is a college graduate?

0.48

Step-by-step explanation:

Let , Event A =Individuals earning more than $38,000.

Event B =Individual have a college degree

Given : The proportion of individuals in a certain city earning more than $38,000 per year :P(A)= 0.25.

The proportion of individuals earning more than $38 comma 00038,000 and having a college degree is P(A and B)= 0.12.

Using conditional probability formula , we have

i.e. Probability that an individual is a college graduate given that he is earning more than $38,000

Hence, the required probability = 0.48

x+y=90

x=30-y=x

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