1. a cylindrical can is to have a volume of 24p . the cost of the material used for the top & bottom of the can is 3 cents/ and the cost of the material used for the curved sides is 2 cents/. express the cost of constructing the can as a function of its radius.

Totalcost = +

Step-by-step explanation:

Given the volume of the can is 24 cubic cm

Also given that it costs 3 cents per square cm on the to and bottom sides And 2 cents per square cm on the curved sides

Let the radius and height of the can be r and h

Now Volume =  π

24  = π

πh =

Now for constructing we use the surface area which is

Total surface area =  lateral surface area + curved surface area

Lateral suface area = 2π

Cost for preparing the lateral surface is lateral surface / cost for top and bottom =

Curved surface area = 2πrh = 2r =

Cost for preparing theCurved surface area is Curved surface / cost for curved  sides =

Totalcost = +

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680