What is the equation of the line described below written in slope-intercept form? the line passing through point (0, 0) and parallel to the line whose equation is 3x + 2y - 6 = 0 y =-2/3 -x y =-3/2x y = 3/2x

Since the line in question is parallel to the line with the equation 3x+2y-6=0, it can be said that they have the same slope. To find the slope of the line with the given equation, transform the given equation to its corresponding slope-intercept form. Hence, the equation is now

y=(-3/2)x+3

the slope is then -3/2

and since the line in question passes through the origin, the equation of this line is then

y=(-3/2)x+0
or simply
y=(-3/2)x

Where is the problems