Abox with an open top has a square base and four sides of equal height. the volume of the box is 96 ft³. the height is 2 ft greater than both the length and the width. if the surface area is 112 ft², what are the dimensions of the box?

Dimension of box = 4 ft x 4 ft x 6 ft

Step-by-step explanation:

Let a be the base side of square, and h be the height.

The height is 2 ft greater than both the length and the width.

                h = a + 2

The volume of the box is 96 ft³.

         Volume = Base area x Height = a² x h = a² x (a+2)  

           a² x (a+2)  = 96

           We will get a = 4 ft

Dimension of box = 4 x 4 x (4+2) = 4 ft x 4 ft x 6 ft

i think the answer is .36

step-by-step explanation:

what i did was only 2.88 divided by 8

afjnawenkfnjaw; enkanwelwaklalejjaw; fij

step-by-step explanation: