Jolene invests her savings in two bank accounts, one paying 4 percent and the other paying 10 percent simple interest per year. she puts twice as much in the lower-yielding account because it is less risky. her annual interest is 3996 dollars. how much did she invest at each rate?

Step-by-step explanation:

       Jolene invests in two bank accounts. The first account gives a 4% interest per year and the second bank gives a 10% interest rate per year.

       She puts twice as much in the lower yielding bank account. Let us denote the amount put in high yielding bank account by . Lower yielding bank account will have .

Interest from lower yielding bank =

Interest from higher yielding bank =

Total Interest per year = $ 3996 =

∴ Jolene invested $ 22200 in higher yielding bank and $ 44400 in lower yielding bank.

step-by-step explanation:

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answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11