Cora says she doesn't need to know the y-intercept of a line to write its equation, just its slope and some other point on the line. is she correct? explain. if cora is correct, explain how to find the equation of a line with a alope of -1/3 that includes the point (2,6).

The equation of line with given slope that include given points is                 3 y + x - 20 = 0

Step-by-step explanation:

According to Cora , if we know the slope and points on a line then we can write the equation of a line .

Since , The equation of line in slope-intercept form is

y = m x + c

Where m is the slope of line , and if we know the points ( x , y ) which satisfy the line then constant term c can be get and the equation of line can be formed .

So , From the statement said above it is clear that she is correct .

Now , Again

Given as :

Slope of a line is m = -

That include points ( 2 , 6 )

Now from the equation of line as  y = m x + c

∴   6 =  - ( 2 ) + c

Or, 6 =  -  + c

So , c = 6 +

or,  c =

∴   c =

So, The equation of line can be written as

 y =   - x +

Or, 3 y = - x + 20

I.e  3 y + x - 20 = 0

Hence The equation of line with given slope that include given points is     3 y + x - 20 = 0   Answer

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: