Cora says he dosen't need to know the y-interce of a line to write its equation, just its slope and some other point on the line. is she correct? explain. if cora is correct, explain how to find the equation of a line with a slope of -1/3 that includes the point (2,6)

Yes, Cora is correct.

The equation of line with point  (2,6) and slope of line (-1/3)

is x + 3y - 20 = 0

Step-by-step explanation:

Yes, the equation of a line can be written using a point and a slope of the line equation.

Cora has used the POINT SLOPE FORMULA, to represent the line equation.

In Point Slope formula:

The equation with slope m and points (x0,y0) can be written as:

(y-y0) =m (x-x0)

Here, the point (x0,y0) = (2,6)

and slope m = (-1/3)

So, the equation can be written as:

Hence, the equation of line with point  (2,6) and slope of line (-1/3)

is x + 3y - 20 = 0

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

7

step-by-step explanation:

yuo ned the activity or vertical angle of the form of 1,7 but 2,2 has a c4,2 as it verticie so i not have a car