Today the engel family went to the zoo. admissions for each person is $50. the parking feeis $16. how many people in the engel family went to the zoo today if $316 was spent?

The total people in the Engel family who went to the zoo is 6.

Step-by-step explanation:

The admission for each person =$50

Parking fee = $16

Let us assume the total member who go to zoo = m

So, Total ticket price for m people = m x (Price of each ticket)

= m x ($500= 50 m

Total money spent by the family =  $ 316

⇒  Parking Fee + Money spent on m tickets  = Total money = $316

⇒ 16 + 50 m = 316

or, 50 m = 316 - 16  = 300

⇒ m = 300 / 50 = 6

or, m = 6

Hence the total people in the engel family  who went to  zoo is 6.

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb