Tutoring services: the community college survey of student engagement reports that 46% of the students surveyed rarely or never use peer or other tutoring resources. suppose that in reality 40% of community college students never use tutoring services available at their college. in a simulation we select random samples from a population in which 40% do not use tutoring. for each sample we calculate the proportion who do not use tutoring. if we randomly sample 100 students from this population, the standard error is approximately 5%. would it be unusual to see 46% who do not use tutoring in a random sample of 100 students?

No, this would not be unusual because 46% is only 1.2 standard errors from 40%

Step-by-step explanation:

Consider the provided information.

The standard error is approximately 5%

Standard error(SE)=0.05

As we know

Here x=46%=0.46 and μ=40%=0.40

Now use the formula:

Substitute the respective values in the above formula.

Hence, this would not be unusual because 46% is only 1.2 standard errors from 40%

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.