Kirsten tried to evaluate the expression \{12\times2-8\} \times 2{12×2−8}×2left brace, 12, times, 2, minus, 8, right brace, times, 2. her work is below. \begin{aligned} & \phantom{=}\{12\times2-8\} \times 2 \text{step }1: \quad& =\{12\times2\} - 16 \text{step }2: \quad& =24-16 \text{step }3: \quad& =8 \end{aligned} step 1: step 2: step 3: ={12×2−8}×2 ={12×2}−16 =24−16 =8 in which step did kirsten first make a mistake?

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just for that im not answering

thats not a system of equations, that is a solution

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two pairs of adjacent sides are of equal length. this implies that one diagonal divides the kite into congruent triangles, and so the angles between the two pairs of equal sides are equal in measure. it also implies that the diagonals are perpendicular.

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