F(x)=-2(x-3)(x+5) convert quadratic functions to standard form

The answer is: f(x) = -2x^2 - 4x + 30

Step-by-step explanation:

Given:

f(x)=-2(x-3)(x+5)

Solve (x-3)(x+5) first, then multiply by -2:

f(x) = -2[(x - 3)(x + 5)]

f(x) = -2[x^2 -3x + 5x - 15]

f(x) = -2[x^2 + 2x - 15]

f(x) = -2x^2 - 4x + 30

Hope this Helps (-:

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this