In a recent survey of high school students, it was found that the average amount of money spent on entertainment each week was normally distributed with a mean of $52.30. suppose you are told that there is an 80% probability that a randomly-selected student spends somewhere between $49.74 and $54.86. what is the standard deviation of the amount of money spent by high school students monthly?

Std dev = 0.50

Step-by-step explanation:

Given that in a recent survey of high school students, it was found that the average amount of money spent on entertainment each week was normally distributed with a mean of $52.30.

Also given that

For 49.74 we have x-mean =

For 54.86 we have x-mean =

Hence we have

he standard deviation of the amount of money spent by high school students monthly=0.50

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6

i think the amount would be $140.62