Determine whether b is in the column space of a. if it is, then write b as a linear combination of the column vectors of a. (use v1, v2, and v3, respectively, for the three columns. if not possible, enter impossible.)a = [(1,3,0); (-1,1,0); (2,0,1)]b= [(2,3,-4)]

b=(13/4, -27/4, -4)

Step-by-step explanation:

A.x=b

x=(a, b, c)

a   - b + 2c = 2

3a + b +  0 = 3

0  + 0 +  c = -4

solving this system

c=-4

a-b=10, 3a+b=3

a=10+b, 3(10+b)+b=3

b=-27/4

a=10-27/4

a=13/4

is there a question here?

step-by-step explanation:

hello,

as we don't know if g(x) is continue,

answer b

f(x)=2x²-8x+1=2(x²-4x+4)+1-8=2(x-2)²-7

vertex is (2,-7) ( a minimum since coefficient of x² is > 0)