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![\bf tan^3(x) = \cfrac{1}{3}tan(x)\implies tan^3(x)-\cfrac{1}{3}tan(x) = 0 \\\\\\ tan(x)\left(tan^2(x)-\cfrac{1}{3} \right)=0 \\\\[-0.35em] ~\dotfill\\\\ tan(x) = 0\implies x = tan^{-1}(x)\implies \boxed{x = n\pi \qquad n\in \mathbb{Z}} \\\\[-0.35em] ~\dotfill\\\\ tan^2(x)-\cfrac{1}{3}=0\implies tan^2(x) = \cfrac{1}{3}\implies tan(x) = \pm \sqrt{\cfrac{1}{3}}](/tpl/images/0384/0449/af932.png)
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Tan^3(x) =1/3tan(x) all the solutions...
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