The path of a projectile launched from a 20 ft tall tower is modeled by the equation y = -16x^2 + 32x + 20 what is the maximum height, in feet, reached by the projectile?

36 feet

Step-by-step explanation:

The given equation is:

To find the maximum height, we complete the square to write the function in the vertex form:

This equation is of the form:

where k=36 is the maximum height reached by the projectile.

i think it will be 4feet long of what i comprehend

show us the triangle so we can answer it