The top and bottom margins of a poster are 2 cm and the side margins are each 8 cm. if the area of printed material on the poster is fixed at 386 square centimeters, find the dimensions of the poster with the smallest area.

Answer :

39.294 cm × 9.823 cm

Explanation :

Let x be the length ( in cm ) of the printed material and y be the width ( in cm ) of the printed material,

So, the area of the printed material,

According to the question,

A = 386 cm²,

Since, the printed area is obtained in the margin of 2 cm from both top and bottom and margin of 8 cm in sides,

Thus, length of the poster = (x + 16) cm and width = (y + 4)

So, the area of the poster,

Differentiating with respect to x,

Again differentiating with respect to x,

For maxima or minima,

Sides can not be negative,

Also, at x = 39.294,

i.e. is minimum at x = 39.294,

∵ y = = 9.823

Hence, the dimensions of the poster with the smallest area,

39.294 cm × 9.823 cm

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

y -5 = (-1/4)(x + 8)

step-by-step explanation: