(y^(2)+1)/(y^(2)-y-6)
(-2,3)
(-1, 6)
Mathematics, 20.11.2019 21:31 xxtonixwilsonxx
What are the excluded value(s)?
(y^(2)+1)/(y^(2)-y-6)
(-2,3)
(-1, 6)
(-2, -6)
Answers: 2
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You know the right answer?
What are the excluded value(s)?
(y^(2)+1)/(y^(2)-y-6)
(-2,3)
(-1, 6)
(y^(2)+1)/(y^(2)-y-6)
(-2,3)
(-1, 6)
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