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you randomly draw marbles from a bag containing 4 blue and 2 green marbles, without replacing the marbles between draws. what is the probability of drawing a green marble on both your first and second draws?
a. 1/2⋅1/4
b. 2/6⋅1/5
c. 2/6⋅1/6
d. 2/6⋅2/6

B)

Step-by-step explanation:

Number of blue marbles =

Number of green marbles=

Total number of balls=

Probability of drawing a green marble on first draw=

After drawing a green marble a 2nd draw is made without replacement.

So, now and

Probability of drawing a green marble on 2nd draw=

∴ Probability of drawing a green marble on both your first and second draws=

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !