How do you write this equation in y=ax^2+bx+c ?

Step-by-step explanation:

y = (x-1)(2x-1)

= x(2x-1) -1(2x-1)

= 2x^2 - x - 2x + 1

= 2x^2 - 3x + 1

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)