The lengths of the sides of a triangle are 3,4, and 6. if the length of the shortest side of a similar triangle is 5, find the length of its longest side.

the length of the longest side of the bigger triangle is 10

Step-by-step explanation:

The illustration of this scenario is shown in the attached photo. The small triangle is triangle ABC and it corresponds to a bigger triangle XYZ. This also means that triangle ABC is similar to triangle XYZ. This means that the ratio of a side on the small triangle to a corresponding side on the bigger triangle is constant or proportional. Therefore,

AB/XY = AC/XZ = BC/YZ

We want to find the length of the longest side of the bigger triangle. Let x = the length of the longest side of the bigger triangle. It becomes

BC/YZ = AC/XZ

6/x = 3/5

3x = 30

x = 30/3 = 10

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204