The ratios of the measures of the sides of a triangle is 4: 10: 7. find the length of each side if the perimeter of the triangle is 252 meters.

First side of the triangle = 48 m

Second side =   120 m

Third side  = 84 m

Step-by-step explanation:

The ratios of the measures of the sides of a triangle is 4:10:7

Let us assume the common ratio of the sides of the triangle = m

So, the first side of the triangle  =  4 m

Second side of the triangle  =  10 m

Third side of the triangle  = 7 m

Now, PERIMETER OF A TRIANGLE = SUM OF ALL SIDES

⇒ 4 m + 10 m + 7 m = 252 m

or, 21 m = 252 m

⇒ m = 252/ 21 = 12

So, the common ratio in the sides is 12.

Hence, the first side of the triangle  =  4 m = 4 x 12   = 48 m

Second side of the triangle =  10 m  = 10  x 12 =  120 m

Third side of the triangle  = 7 m = 7 x 12  = 84 m