Find three consecutive even integers such that the product of the first and the third is 96

Step-by-step explanation:

x,x+2,x+4 are the consecutive even integers

x(x+4)=96

X^2 +4x =96

x^2 +4x =96

x^2 +12x-8x -96=0

x(x+12)-8(x+12)=0

(x+12)(x-8)=0

Therefore x=8 or-12

x=8

Consecutive even integers are 8,10,12

do you mean add both of the equations together

because if you do the answer is 10x-5

step-by-step explanation: