Which equation describes this line?
(1.13)
(-2.4)
o a. y-1 = 3(x - 13)
o b. y= 2 = 3(x-4)
o c. y - 4 = 3 (x - 2)
o d . y - 4 = 3(x + 2)

The equation of line with given points is  y - 4 = 3 ( x + 2 ) .

Step-by-step explanation:

Given as :

The points of line are ( 1 , 13 )   and    ( - 2 , 4 )

The point slope intercept equation of line is

y - = m ( x -   )

Where m is the slope of line

So , Slope , m =

Or, m =  

Or, m =  

∴    m = 3

Now The equation of line is

y - = m ( x -   )

Or. y - 13 = 3 ( x -  1 )

Or, y - 13 = 3 x - 3

Or, y = 3 x - 3 + 13

∴   y = 3 x + 10

I.e y - 4 = 3 x + 6

Or, y - 4 = 3 ( x + 2 )

Hence The equation of line with given points is  y - 4 = 3 ( x + 2 ) . Answer

fourth month

step-by-step explanation:

it is the one with the most keychains.

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17