Let x represent the full height of a certain species of tree. assume that x has a normal probability distribution with mean 36.4 ft and standard deviation 39.6 ft. you intend to measure a random sample of n=97 trees. the bell curve below represents the distibution of these sample means. the scale on the horizontal axis is the standard error of the sampling distribution. complete the following, correct to two decimal places.
μ¯x = σ¯x =

μ¯x = 36.4 ft

σ¯x = 4.02

Step-by-step explanation:

μ = 36.4 ft

σ = 39.6 ft

n = 97 trees

The mean of a sampling distribution will be the mean of the population/probability distribution. So in this example, it would be 36.4 feet.

μ¯x = μ = 36.4 ft

The standard deviation of the sampling distribution, what is also referred to as standard error, is the standard deviation of the population/probability distribution divided by the square root of the sample size (n). So in this example, it would be 39.6 divided by the square root of 97:

σ¯x = σ / √n   ⇒   σ¯x = 39.6 / √97 = 4.02

stew reads at the fastest rate of 265 words per minute.

step-by-step explanation:

it's a given that felicia reads at 260 word per minute and on connie's graph we can see that she reads 200 words per minute. since stew's table tells us that he read 795 in 3 minutes, we can divide 795 by 3 to find out how many words he reads per minute.

795/3 = 265

stew reads 265 words per minute - he reads at the fastest rate since felecia reads at 260 words per minute and connie reads at 200 words per minute.

stew (265) > felecia (260) > connie (200)