Acity's buses delayed time (x) is uniformly distributed between [0,y] where 0 < = y < = 1 and is uniformly disturbed. suppose you observe a delay time x=x. a) compute the posterior distribution of y given the data observed and find an approximate value of y by calculating e(y | x=x) b) suppose the first delay you observe is x(1) = 0.5. the next delay is independently drawn by the same distribution (x(2) ~ uniform [0,y]. given what you have observed from the first delay, what is the probability that the second delay will be more than a 0.5 hour delay?

i dont know sorry

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he can buy 4lbs. of live bait and 1lbs of natural bait

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hello,

b) 62.47% of the students are between 14 and 18 years old.

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mean = 15 and standard deviation = 2

student between 14 to 18

formula used z-score

for age 14 , z score

using z-table , p(z> -0.5)=0.3085

for age 18 , z score

using z-table , p(z< 1.5)=0.9332

p(-0.5< z< 1.5)=0.9332-0.3085 = 0.6247

thus, 62.47% of the students are between 14 and 18 years old.

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