Two triangles are shown to be congruent by identifying a combination of translations, rotations, or reflections that move one figure onto the other. if δmop ≅ δcup, which angle must be congruent to ∠cpu? why?

In the given question,

Δ MOP ≅ Δ CUP

so, ∠MPO ≅ ∠CPU

Step-by-step explanation:

As when we write Δ ABC ≅ Δ DEF (1)

it means that the points are taken in such an order that the congruent sides and angles can be easily found from the notation, i.e., if we take sides and angles from the notation of RHS in the same order as those taken from the notation in LHS, then the corresponding sides and angles will be congruent.

e.g., from (1)

∠ACB ≅ ∠DFE

but, ∠ ABC  is not congruent to ∠ EDF

and,

AB ≅ DE but,  AC  is not congruent to EF.

Now, in the given question,

Δ MOP ≅ Δ CUP

so, ∠MPO ≅ ∠CPU

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -