Evaluate upper e equals z superscript star baseline startroot startfraction modifyingabove p with caret 1 times modifyingabove q with caret 1 over n 1 endfraction plus startfraction modifyingabove p with caret 2 times modifyingabove q with caret 2 over n 2 endfraction endroot e=z* p1• q1 n1 + p2• q2 n2 for z superscript star z* equals 2.575, x1 equals 41 41, x 2 x2 equals 75, n1 equals 47, n2 equals 91, modifyingabove p with caret 1 p1 equals startfraction x 1 over n 1 endfraction x1 n1 , modifyingabove q with caret 1 q1 equals 1 minus − modifyingabove p with caret 1 p1, modifyingabove p with caret 2 p2 equals = startfraction x 2 over n 2 endfraction x2 n2 , and modifyingabove q with caret 2 q2 equals 1 minus − modifyingabove p with caret 2 p2.

State whether weight is a function of height for the six students and explain. a. yes, height is a function of weight because two students weigh 165 pounds but have different heights. b. no, height is not a function of weight because two students weigh 165 pounds but have different heights. c. yes, weight is a function of height because for each value of height there is one corresponding value of weight. d. no, weight is not a function of height because there is not enough data to determine a function.

Divide the following fractions 3/4 ÷ 2/3 1/2 8/9 9/8 2

Determine if the following statement is true or false. the normal curve is symmetric about its​ mean, mu. choose the best answer below. a. the statement is false. the normal curve is not symmetric about its​ mean, because the mean is the balancing point of the graph of the distribution. the median is the point where​ 50% of the area under the distribution is to the left and​ 50% to the right.​ therefore, the normal curve could only be symmetric about its​ median, not about its mean. b. the statement is true. the normal curve is a symmetric distribution with one​ peak, which means the​ mean, median, and mode are all equal.​ therefore, the normal curve is symmetric about the​ mean, mu. c. the statement is false. the mean is the balancing point for the graph of a​ distribution, and​ therefore, it is impossible for any distribution to be symmetric about the mean. d. the statement is true. the mean is the balancing point for the graph of a​ distribution, and​ therefore, all distributions are symmetric about the mean.