In a recent poll, 200 people were asked if they liked skiing, and 19% said they did. based on this, construct a 99% confidence interval for the true population proportion of people who like skiing. as in the reading, in your calculations: a. -use z = 1.645 for a 90% confidence interval b. use z = 2 for a 95% confidence interval c. use z = 2.576 for a 99% confidence interval. give your answers as decimals, to 4 decimal places.

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

sorry

step-by-step explanation:

sorry, but im pretty sure its a now that i look at it

hello! just here for points! though i wish i knew!

i'm a sophomore in connections, i'd recommend checking on jishka.com they have a large range of questions and answers from our school.