Write the equation of the line with slope 3 that passes through the point (-1,6) in slope-intercept form

Step-by-step explanation:

By knowing the slope of the line, and one point it has to go through, we can easily write the equation of the line by starting with the general form of a line in "point-slope" form. That is a line of slope "m" and going through the point on the plane, can be written in its "point-slope" form as:

and subsequently solving for "y" in the equation to get it in its "slope-intercept" form.

Therefore, in our case, with slope (m) equal to 3, and the point equal to (-1, 6), we get:

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m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true