Ahollow steel shaft transmits 600 kw at 500 rpm. the maximum shear stress is 62.4 mpa. find the outside diameter of the shaft, if the outer diameter is twice the inside diameter, assuming the maximum torque is 20% greater than the mean torque

maybe showing the graph would

step-by-step explanation:

-387129 iq

what is the original number? you forgot to add it.

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!

answer4 to the second power is 16

and 4 to the third power is 64,