Mathematics, 17.11.2019 01:31 miguel3maroghi
An object is launched vertically in the air at 32.83 meters per second from a platform 10m above the ground. the height of the object above the ground (in meters) t seconds after launch is given by h(t)= -4.9t^2 + 32.83t +10 how long does it take the object to reach maximum height? what is the objects maximum height?
Answers: 2
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