Let f(x)=2−|4x−2|. show that there is no value of c such that f(3)−f(0)=f'(c)(3−0). why does this not contradict the mean value theorem?

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.

one peck is 9.309 quarts

9.309x 2

the answer should be:

a. 3, 4, and 6

b. 18, 24, and 36

c. 4.8, 6.4, and 9.6

hope i

-lavira : )

u get 2 big as balls