In the game of blackjack played with one deck, a player is initially dealt 2 diferent cards from the 52 different cards in the deck a winning ℡ack ack hand is won by getting 1 of the 4 aces and 1 of 16 other cards worth 10 points. the two cards can be in any order. find the probability of being dealt a blackjack hand. what approximate percentage of hands are winning blackjack hands?
the probability is □ type an integer or a simplified fraction)
the percentage of hands that are winning blackjack hands is round to two decimal places as needed.)

4.83%

Step-by-step explanation:

Total number of possible hands

we are interested in selecting two of the 52 cards in the deck.

n=52

r=2

therefore,

52C_2 = 52!/(2!50!)= 1326 possible hands

therefore total number of blackjacks

A blackjack consists of 1 of 4 aces and 1 of 16 other cards that are worth 10 points.

by fundamental counting rule

4*16= 64 possible blackjacks

2)% of hands that are winning blackjack hands =(32/663)*100 =4.83%

this linear equation would have just one solution.

step-by-step explanation:

the reason why this would have one solution is that it is an expression with just one variable. since that variable is not raised to a power, it will always have just one solution.