5.4 find the p-value, part ii. an independent random sample is selected from an approximately normal population with an unknown standard deviation. find the p-value for the given set of hypotheses and t test statistic. also determine if the null hypothesis would be rejected at α = 0.01. (a) ha : µ > 0.5, n = 26, t = 2.485 (b) ha : µ < 3, n = 18, t = 0.5

a) reject, b) accept

Step-by-step explanation:

We assume one sided test, and by looking at a t table which is one sided we can get the p values.

We have:

α = 0.01

a) µ > 0.5, n = 26, T = 2.485

we have degrees of freedom

n = 26 so

now we look at the table in row which index is 25 and see the closest number to we can find.

We find that number to be exactly 0.01 which is exactly equal to the critical value α, unfortunately 0.01 is not greater than 0.01 so we have to reject the hypotesis.

b) µ < 3, n = 18, T = 0.5

we do the same, this time , now we find that the closest value to 0.5 is 0.689, we can not find an exact value!, so what we do is say that the probability lies between the probability of the closest values to our number, looking at the table, 0.257 and 0.689 are the references we have, and their respective probabilities are 0.4 and 0.25,

so we just say that p is between 0.4 and 0.25.

Now we have that either value is greater than α, so we accept the hypotesis

use an equation of ratios to determine the amount of gas needed to fill the tank.

    0.2             0.8

  =    

288.75             x

                                                              231 gal

so, 0.2x = (0.8)(288.75 gal), and x = = 1155 gal.

                                                                0.2

it would take 1155 gal. to fill the tank.

the cost would be

1155 gal         $3

* = $3465   (answer)

      1           1 gal

hope this you