Among 500 freshmen pursuing a business degree at a university, 343 are enrolled in an economics course, 218 are enrolled in a mathematics course, and 138 are enrolled in both an economics and a mathematics course. what is the probability that a freshman selected at random from this group is enrolled in each of the following? (enter your answers to three decimal places.)

P(M) = 0.160

P(E) = 0.410

Step-by-step explanation:

The Universal set = 500

Let E represent economics and M represent Mathematics , then

n(E) = 343

n (M) = 228

n ( E n M ) = 138

Therefore :

n (E) alone = 343 - 138

                  = 205

Also n(M) alone = 228 - 138

                          = 80

Therefore probability of Mathematics is given by:

P(M) = n(M) alone / Total number

P(M) = 80/500

P(M) = 0.160

P(E) = n(E) alone / Total number

P(E) = 205/500

P(E) = 0.410

easy its decreasing

step-by-step explanation:

because its top point is at the to of the graph on the left side (atleast from the veiw i see it) now if that top point wast in the lower part of the graph it would be increasing hope this have a nice day