Information on a packet of seeds, which may not be a random sample of seeds, claims that the germination rate is 94%. what's the probability that more than 96% of the 220 seeds in the packet will germinate? be sure to discuss your assumptions and check the conditions that support your model.

0.1052

Step-by-step explanation:

Given that proportion of germination in the population is 94% =0.94

p = 0.96

Sample size = 220

Std dev of p =

The probability that more than 96% of the 220 seeds in the packet will germinate

=

Assumptions are np and nq >5 and also sample size >220 hence normal

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

maya’s expression will generate the wrong sum because she violated the commutative property.

step-by-step explanation: