Given a normal distribution with image for (a)the normal -curve area to the right of x=17. (b)the normal-curve area to the left of x=22. (c)the normal-cu and image for (a)the normal -curve area to the right of x=17. (b)the normal-curve area to the left of x=22. (c)the normal-cu , find

(a)the normal -curve area to the right of x=17.
(b)the normal-curve area to the left of x=22.
(c)the normal-curve area between x=32 and x=41
(d)the value of x that has 80% of the normal-curve area to theleft.
(e)the two values of x that contain the middle 75% of thenormal-curve area

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1

a is 8.b is 10.c is 10.5. d is -.5

step-by-step explanation:

just minus the smallest number from the biggest.