In a survey of 100 adults, 91 of them said that they trusted dna testing. a. what is pˆ , the sample proportion of adults who trust dna testing? b. find and interpret the 98% confidence interval for the proportion of adults that trust dna testing

a) The sample proportion of adults who trust DNA testing is p=0.91.

b) 98% CI:

We can claim with 98% confidence that the real proportion of adults that trust DNA is between 0.84 and 0.98.

Step-by-step explanation:

a) In this problem, we calculate p-hat, the sample proportion of adults who trust DNA testing, as

b) The z-value for a 98% CI is z=2.326.

The standard deviation of the proportion is:

Then we can define the CI as:

We can claim with 98% confidence that the real proportion of adults that trust DNA testing is between 0.84 and 0.98.

maya’s expression will generate the wrong sum because she violated the commutative property.

step-by-step explanation: