The lifetime of an led in a certain application is normally distributed with a mean μ = 25,000 hours and a standard deviation σ = 1500 hours. a. what is the probability that a light bulb will last more than 24,000 hours?

0.7477

Step-by-step explanation:

The mean(X) = 25,000 hrs

Standard deviation (σ) = 1500 hrs

The probability that the light bulb lasts more than 24,000hrs is Pr (X˃24,000)

Using Z-scores, Z= (X- μ)/σ

For X = 24,000

Z = (24,000 – 25,000)/1500

Z = -1000/1500

Z = -0.667

From the normal distribution table, Z= 0.667 = 0.2477

Φ(Z) = 0.2477

Recall that if Z is negative,

Pr (X˃a) = 0.5 + Φ(Z)

Pr (X˃24,000) = 0.5 + 0.2477

= 0.7477

44

step-by-step explanation:

160

step-by-step explanation:

idk

i hope i